Table II.

Case

Assumption

Conclusion

Proof

I.

either or for some and in the latter case for at least one index among the components of sk there occur one(s) with zero and other(s) with positive value

is not bounded from below on K

Theorem 4.1

II.

 for every where

 takes on its minimum on K

Lemma 5.1

III.

For some vector the following hold:
a) ;
b) for every index either sk >> 0 or sk = 0;
c) sk >> 0 is fulfilled for at least one index ;

the nonlinear part of can be shortened

Theorem 6.1

IV.

For some vector the following hold:
a) ;
b) sk >> 0 for every ;

can be reduced to a linear function

Theorem 6.2